16x^2-14x-11=0

Solution for 16x^2-14x-11=0 equation:

16x^2-14x-11=0

a = 16; b = -14; c = -11;
Δ = b2-4ac
Δ = -142-4·16·(-11)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-30}{2*16}=\frac{-16}{32}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+30}{2*16}=\frac{44}{32}
=1+3/8
$